The mouseY is bigger than > the upper side The mouseX is bigger than > the left side of the rect (or the upper left corner if you like) When the mouse button is released, we'll get the mouse X. When the mouse is held down, we'll get the X and Y coordinates of where the mouse is at that point. If the mouse is inside the rectangle it means that: The technique we'll use to draw on our Picture Box surface is this: hold your left mouse button down on the Picture Box, keep it held down, drag to the right, release the left mouse button. Now, we want to check the position of the mouse against an area on the screen, let's say a rectangle: I mean mouseX, and mouseY is the mouse position (x goes to the right, y to the bottom). Bored out of your skull Bored enough to stare at some lackluster sprites for an hour Then MouseX, MouseY is right up your alley Move your poorly designed cursor away from the poorly designed enemies to survive. You should be able to work the rest out from here on your own. It means that the mouse is on the LEFT HALF of the sketch! When the mouse button is released, we'll get the mouse X and Y coordinates again.
#Pmouse x pmouse y pro#
PRO X SUPERLIGHT hace gala de nuestra tecnologa de diseo ZER OPOSICIN, nuestro propsito de eliminar obstculos y crear una conexin lo ms pura posible entre el. The technique we'll use to draw on our Picture Box surface is this: hold your left mouse button down on the Picture Box, keep it held down, drag to the right, release the left mouse button. El nuevo favorito de los mejores profesionales de esports pesa menos de 63 gramos y se desliza sin apenas friccin. What does it mean for mouseX to be less than half the sketch's width? Elimina todos los obstculos para ganar con nuestro mouse inalmbrico PRO ms ligero y rpido. What is width / 2? Half the width of the sketch! The criteria is that mouseX is less than width / 2. What does the second conditional say? Like the first, it is doing a comparison with mouseX, so you know it is checking if the mouse's X position meets some criteria. This first conditional makes sure that the mouses X position is greater than zero. if (mouseX > 0 & mouseX 0 & mouseY 0 & mouseX 0 & mouseY 0 If you did, you should be able to do this yourself.
#Pmouse x pmouse y code#
If (!ONLINE) tTitle("Quadrant: " + quadrant) Įlse if (mx >= cx & my < cy) quadrant = "Top-Right" ĭo you understand - at all - what the code on line 11 says? If you would like to get help with your new problem, you should post a new question to keep things tidy and more likely for others to be able to help you or find your question if they are having a similar problem. * /two/discussion/15129/mousex-and-mousey If this solution I posted solved the original problem you were having, you should accept it as the answer.
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